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Suppose that $10,473 is invested at an interest rate of 6.1 % per year, compounded continuously. a) Find the exponential function that describes the amount

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Suppose that $10,473 is invested at an interest rate of 6.1 % per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t. in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t) = 10473 e 0'06" . (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any numbers in the equation.) b) The balance after 1 year is $ 11131.?4'. (Simplify your answers. Round to two decimal places as needed.) The balance after 2 years is $1 1831.91 . (Simplify your answers. Round to two decimal places as needed.) The balance after 5 years is 5 13007.93 . (Simplify your answars. Round to two decimal places as needed.) The balance after 10 years is $3927484 (Simplify your answers. Round to two decimal places as needed.) 6) The doubling time Is D years. (Simplify your answers. Round to one decimal place as needed.)

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