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Suppose that instead of always selecting the first activity to finish, we instead select the last activity to start that is compatible with all previously

Suppose that instead of always selecting the first activity to finish, we
instead select the last activity to start that is compatible with all previously selected activities. Describe how this approach is a greedy algorithm, and prove that it yields an optimal solution. **Do so by proving the greedy choice property and showing the optimal substructure.**

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