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Suppose that it is given to you that f'(x) = (x+3)(6 -x)(x - 14) Then the first relative extremum (from the left) for f(x) occurs
Suppose that it is given to you that f'(x) = (x+3)(6 -x)(x - 14) Then the first relative extremum (from the left) for f(x) occurs at r = -3 The function f(x) has a relative |max V at this point. The second relative extremum (from the left) for f(x) occurs at = 6 The function f(a) has a relative min Vat this point. The third relative extremum (from the left) for f(x) occurs at a = 14 The function f(x) has a relative max at this point. The first inflection point (from the left) for f(x) occurs at * = The second inflection point (from the left) for f(x) occurs at * =Let f(x) = 4+ 27x - 2 . Find (a) the intervals on which f is increasing, (b) the intervals on which f is decreasing, (c) the open intervals on which f is concave up, (d) the open intervals on which f is concave down, and (e) the x-coordinates of all inflection points. (a) f is increasing on the interval(s) (b) f is decreasing on the interval(s) (c) f is concave up on the open interval(s) (-infinity ,0) (d) f is concave down on the open interval(s) (0, infinity ) (e) the x coordinate(s) of the points of inflection are 0 Notes: In the first four boxes, your answer should either be a single interval, such as [0, 1), a comma separated list of intervals, such as (-inf, 2), (3,4], or the word "none". In the last box, your answer should be a comma separated list of a values or the word "none"
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