Suppose that out of 150 doctor visits, 134 of them were for reasons unrelated to food and 16 were for food related reasons Considering only these two possible categories of outcomes (food related and non food related), calculate the probability of seeing 134 or more non food visits assuming that the underlying true proportion of non food related problems in the population is 0.8.

(I have calculate this below)

pbinom

( q=134,size=150,prob = 0.8 )

dbinom

(x=0:134,size=150,prob = 0.8)

[1] 0.9992424 [1] 0.9992424

How can I

1. Report the probability ? and 2. Explain what each of my calculations is doing?