Suppose that the professor who teaches the course wants to know the mean GPA of the students enrolled in his course. He selects a sample of students who are in attendance on the third day of class. The GPAs of the students in the sample are: 3.50 3.60 3.47 3.39 3.43 3.09 2.95 2.94 3.20 3.53 The instructor uses the sample average as an estimate of the mean GPA of his students. The absolute value of the error in the instructor's estimate is: O 0.62 O 0.52 o 0.22 O 0.86 The portion of this error that is due to errors in data acquisition, nonresponse bias, and selection bias is referred to as V . This type of error is V serious than V because taking a larger sample V its size or possibility of occurrence. Suppose students in the university's honors program are on a eld trip on the third day of class. This may have introduced V . Correcting this error will V . Suppose that the instructor incorrectly recorded the value 3.60 in the data and that the correct value is 3.06. This contribution to the error was caused by V . Given the instructor's sample, correcting this error would bring the sample mean v Suppose a student who was selected for the sample declines to disclose her GPA. This may have introduced a nonresponse error v . Correcting this error will v . The professor suspects that his sample is awed. He assigns each of the students in the class an ID number from 1 to 63 and uses Excel to select a simple random sample of ID numbers. The professor meets with the students in the sample. Each student signs a release that gives the registrar permission to use the student's GPA to compute the sample average. The professor assures the students that the registrar will provide her with the average and not the GPAs of individual students. The GPAs of the students in the new sample (from their academic records held by the registrar) are: 3.15 3.24 3.12 3.05 3.09 2.78 2.66 2.65 2.88 3.18 The professor uses the new sample average provided by the registrar as an estimate of the mean GPA of the students in the course. The absolute value of the error in his estimate is: A 0.26 x"; 0.13 A 0.19 O 0.52 This error is V , and the only way to reduce its expected size is to v the sample size