Suppose that the second order linear equation x2dx2d2y+(2xx3)dxdy+4y=0 has a fundamental set of solutions {y1,y2} such that y1(1)=4,y1(1)=3,y2(1)=5 and y2(1)=5. Then find explicitly the Wronskian w(x)=y1(x)y2(x)y2(x)y1(x) in x>0. We have w(x)= Given that y=x is a solution of (x2(2+x2))dx2d2y(6x+2x3)dxdy+(6+2x2)y=0 in x>0, find another solution yc of the same equation such that {x,yc(x)} is a fundamental yc= Find a single solution of y as a function of t if y=2. y(t)=