Question
Suppose that the wingspan of an adult sparrow, X, follows an approximately normal distribution with a population mean of 49.3 inches and standard deviation of
Suppose that the wingspan of an adult sparrow, X, follows an approximately normal distribution with a population mean of 49.3 inches and standard
deviation of 1.89 inches (X ~ N(meanx = 49.3, SDx = 1.89)).
a. What is the probability that an adult sparrow has a wingspan greater than 52.3 inches in length (round your answer to 3 decimal places).
b. What is the probability that an adult sparrow has a wingspan less than 48.904 inches in length (round your answer to 3 decimal places).
c. 18% percent of sparrows are expected to have a wingspan greater than a certain length what is this length (round your answer to two decimal places)? Before you answer the question think about what percentile I am asking for.
d. What is the 25% of sparrow wingspan lengths (round to three decimal places)?
e. does the z-score indicate that this is a typical wind span for a sparrow?
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