Suppose that X is an RV with mean 20 and variance 10. Use Chebyshev's inequality to upper bound the probability that X is NOT between 15 and 25, or P(X 25).Consider a random graph with n nodes. Each pair of nodes (a tuple) can be connected with an edge with probability 19. For arbitrary nodes: a, b, c, d in the graph, the event a, b are connected is independent of the event c, d are connected. You can imagine the graph to be a social network with 71. people, in which each pair of people can be friends at random. The event of being friends is independent of other pairs of people being friends. Given n = 7,1) = 3) Use the union bound to give an upper bound of the event in which there exists a node that is not connected with any other node