Suppose that you are dealt the following hand in poker from a standard deck of 52 cards

You decide to exchange the 2, the 3, and the 4 by discarding them and drawing 3 more cards from the remaining 47 in the deck. (So you CANNOT draw one of the 3 cards which you just discarded.) What is the probability that you end up with 2 pairs (meaning 2 cards of one denomination, 2 cards of a different denomination, and one card of a third denomination) in your hand? Show your work please step by step