Suppose the employee satisfaction level of all human resource employees in a worldwide corporation is normally distributed with an unknown population mean and standard deviation. a random sample of all employees is taken. find the count, sample mean, and the standard deviation of hr employees. use excel to find the margin of error for 95% confidence interval estimate for the population mean.

Correlation Coefficient |r Coefficient of Determination |r2 e Least Squared Regression Line y-hat Interpret the meaning of r and r-squared. r r^2 Null Hypothesis status quo Alternative Hypothe two tail test test statistic r/Sqrt((1-r^2)/{n-2)) p-value lower tail upper tail two tail conclusion Use the regression line to estimate the average monthly hours worked if an employee's last evaluation score was 0.50 and interpret the result.Sample Size (n) Sample Mean (x-bar) Sample Std Dev (5) Hypothesized Value (u) Alternative Hypothesis Standard Error #N/A Test Statistic (t) #N/A p value (lower tail) #N/A p value (upper tail) #N/A p value (two tail) #N/A significant level (alpha) appropriate p value ConclusionINPUT DATA OR EXCE LIST EXCEL FUNCTION Sample Size (n) given x-bar given S given Confidence Level given alpha Margin of Error Point Estimate (x-bar) Lower Limit Upper Limit Conclusion