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Suppose the graph of y = f(m) is translated right 5 units, and down 5 units, then stretched vertically by a factor of 5. The
Suppose the graph of y = f(m) is translated right 5 units, and down 5 units, then stretched vertically by a factor of 5. The new graph will have equation y = (5(25 7 5) i 5) x The graph below shows points on the xy-plane. It represents a function, but the function is not invertible. 10 1 2 3 4 5 6 7 8 9 10 11 What is the least number of points that could be removed in order to make the remaining points represent y as an invertible function of ac? Answer: 4 X
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