Suppose the Maclaurin series of a functionf(x) isf(x) =

n=0

1

2

n

+4

x

n

{"version":"1.1","math":"\(\sum_{n=0}^\infty \frac{1}{2^n+4}x^n\)"}.Then the 5-th derivative of this function atx= 0 isf⁽⁵⁾(0) =

Question 11 options:

a)

40

11

{"version":"1.1","math":"\frac{40}{11}"}

b)

120

11

{"version":"1.1","math":"\frac{120}{11}"}

c)

1

33

{"version":"1.1","math":"\frac{1}{33}"}

d)

10

3

{"version":"1.1","math":"\frac{10}{3}"}

e)

24

7

{"version":"1.1","math":"\frac{24}{7}"}

f)

60

17

Suppose the Maclaurin series of a function f (x) isf(x) = _ _onyx". Then the 5-th derivative of this function at x = 0 is f(5)(0) = O a) 40 11 O b ) 120 11 O c) 33 O d) 10 3 O e ) Of)