Suppose the score of a test follows a normal distribution N(400, 60). How do you find the percentile that separates the top 10% of the test takers from the rest? Find the z-score that has the closest probability to 0.90 from the z-table and covert it to the test score using 400 + 60*z Find the z-score that has the closest probability to 0.10 from the z-table and covert it to the test score by calculating 60 + 400*z O Find the z-score that has the closest probability to 0.90 from the z-table and covert it to the test score by calculating 400 - 60*z Find the z-score that has the closest probability to 0.10 from the z-table and covert it to the test score by calculating 400 + 60*z