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Suppose trains heading for destination A arrive at the station every 15 minutes, starting at 7 A.M., while trains heading for destination B arrive at

Suppose trains heading for destination A arrive at the station every 15 minutes, starting at 7 A.M., while trains heading for destination B arrive at the station every 15 minutes, starting at 7:05 A.M.

Suppose also that a passenger arrives at the station at a time uniformly distributed between 7 and 8 A.M., and then adventurously hops on the first train to arrive.

What is the probability this passenger waits 5 minutes or less? Do NOT round your answer. (4th decimal place of answer = 6)

Please send me answer fast, it's urgent.

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