Suppose we want to estimate the proportion of college students who have a high level of stress. A sample of 253 253 college students was collected and found that 56 56 of them had high levels of stress. Previously, we found that the estimated standard deviation for the sample proportion is 0.03 0.03. Calculate the margin of error that would be used to create a 95 % 95% confidence interval for the population proportion of students who had a high level of stress. Round to 4 4 decimal places. = ME=