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Suppose you collect data regarding the number of text messages (dependent variable) sent in the last hour from a sample of students. Also, suppose you

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Suppose you collect data regarding the number of text messages (dependent variable) sent in the last hour from a sample of students. Also, suppose you know that on average, people send about 2 (u=2) text messages per hour. You want to know if your sample of students sends significantly more text messages than people on average. Below are the SPSS results One-Sample Statistics Std, Error N Mean Std. Deviation Mean NumberOfTextMsgsSenti 39 2.90 1.744 279 nLastHour One-Sample Test Test Value = 2 95% Confidence Interval of the Mean Difference df Sig. (2-tailed) Difference Lower Upper NumberOfTextMsgsSenll 3.213 3B .003 897 .33 1.46 nLastHour One-Sample Effect Sizes Point 95% Confidence Interval Standardizer Estimate Lower Upper NumberOfTextMsgsSent| Cohen's d 1.744 .515 177 846 nLastHour Hedges' correction 1.779 504 174 829 a. The denominator used in estimating the effect sizes. Cohen's d uses the sample standard deviation. Hedges' correction uses the sample standard deviation, plus a correction factor. Fill out the following information: In order to examine whether for your students differed from dependent variable the population, a was conducted. It was found that the sample type of statistical test sent text messages (M = , SD = )than the population, significantly more, significantly mean st. dev. fewer, a similar number of with a mean difference of 1 ( ) = P= mean difference df t-value p (sig) value 95% CIL, d = lower CI upper CI Cohen's d

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