T = 17.06/20 = 0. 8530 ? We will also need to square the periods to graph them against the total mass, whose best-fit line will reveal the spring constant. Total mass on Time for 20 Period, T (s) T2 spring, m (kg) cycles (s) 0.100 17.06 0.8530 0.7276 0.200 20.57 1.029 1.058 0.300 24.25 1.213 1.470 0.400 27.23 1.362 1.854 0.500 29.95 1.498 2.243 The slope of the line is electronically determined to be 4.2866, and so the spring constant is: k = 4.2866 =4 9.210 N/m We can compare this value to the one we found in part A, and observe a small difference: T2 vs. Total mass 2.5 y = 4.2866x + 0.1536. 2 1.5 0.5 0.1 0.2 0.3 0.4 0.5 0.6 Total mass (kg) 9.625-9.210 100=4.41% 9.625+9.210