Table 2 - Present Value of an Ordinary Annuity of $1 at Compound Interest Period 1 2 10 11 12 13 14 15 16 17 5 070 0.952 1.859 2.723 3.546 4.329 5.076 5.786 6.463 7.108 7.722 8.306 8.863 9.394 9.899 10.380 10.838 11.274 6 070 0.943 1.833 2.673 3.465 4.212 4.917 5.582 6.210 6.802 7.360 7.887 8.384 8.853 9.295 9.712 10.106 10.477 7 070 0.935 1.808 2.624 3.387 4.100 4.767 5.389 5.971 6.515 7.024 7.499 7.943 8.358 8.745 9.108 9.447 9.763 3 "in 0.926 1.783 2.577 3.312 3.993 4.623 5.206 5.747 6.247 6.710 7.139 7.536 7.904 8.244 8.559 8.851 9.122 9 970 0.917 1.759 2.531 3.240 3.890 4.486 5.033 5.535 5.995 6.418 6.805 7.161 7.487 7.786 8.061 8.313 8.544 1 D "/0 0.909 1.736 2.487 3.170 3.791 4.355 4.868 5.335 5.759 6.145 6.495 6.814 7.103 7.367 7.606 7.824 8.022 119/0 0.901 1.713 2.444 3.102 3.696 4.231 4.712 5.146 5.537 5.889 6.207 6.492 6.750 6.982 7.191 7.379 7.549 1 270 0.893 1.690 2.402 3.037 3.605 4.111 4.564 4.968 5.328 5.650 5.938 6.194 6.424 6.628 6.811 6.974 7.120 Using the previous table, enter the correct factor for three periods at 5%: Periodic payment x Factor = Present value $6,000 x 2.723 $16,338 The controller at Bolden has determined that the company could save $6,000 per year in engineering costs by purchasing a new machine. The new machine would last 12 years and provide the aforementioned annual monetary benefit throughout its entire life. Assuming the interest rate at which Bolden purchases this type of machinery is 9%, what is the maximum amount the company should pay for the machine? $ (Hint: This is basically a present value of an ordinary annuity problem as highlighted above.) Assume that the actual cost of the machine is $50,000. Weighing the present value of the benefits against the cost of the machine, should Bolden purchase this piece of machinery? No