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[ text { String leftmost_one(int } x text { ) } ] Namely, the leftmost_one method should return a mask indicating the leftmost 1 in
\[ \text { String leftmost_one(int } x \text { ) } \] Namely, the leftmost_one method should return a mask indicating the leftmost 1 in the input number x. For example: Moreover, you must implement this function using only straightline code (i.e., no loops or conditionals 1 ) and a limited number of arithmetic and logical operators. Specifically, you are only allowed to use the following operators: ,&,>>,>>,1, Your code should contain a total of at most 15 arithmetic, bitwise, and logical operations. To return your solution as a String with hexadecimal format, you should use the in-built Java function: - String.format( " 0x%08X ", z), where z is a int variable. For instance, System.out.println( String.format( " 0x%08 ", 65280) prints 0x0000FF00. Hint: First transform x into a bit vector of the form [0 . . 011111], where you turn any bit to right of the left most
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