textbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X *Dashboard X C D File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas find cards saved o... Other Bookmarks 1 1 7 - 90% + 1. (10 points) Suppose the supply function for a certain item is given by S(x) = x3+10x, and the demand function is given by D(x) = 900-20x-x , determine the following: a) Find the equilibrium point. la b) Find the consumer surplus at the equilibrium point. 2 1b) c) Find the producer surplus at the equilibrium point. 3 1c) 10100 Let p = D(x) be the consumer's demand function. The consumer's surplus is defined for the equilibrium point (q*, p*) as: Consumer Surplus=CS=So D(x)dx - p*q" Let p = S(x) be the producer's supply function. The producer's surplus is defined for the equilibrium point (q*, p*) as: Producer's Surplus=PS=p*q* - So S(x)dxtextbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X Dashboard X C D File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas find cards saved o... Other Bookmarks 2 / 7 | - 90% + 2. (7 points) A box with an open top is to be constructed from a square piece of cardboard with dimensions 4 cm x 4 cm. This box is constructed by cutting out a square from each of the four corners and bending up the sides. Find the largest volume that such a box can have. 2 3 2 10100 3. (4 points) Let f (x, y, z, w) = 45x3z - - + wz3 . Evaluate f (0, -1,2,1) :textbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X Dashboard X C D File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas find cards saved o... Other Bookmarks 3 / 7 - 79% + 4. (24 points) Given f(x, y) = -3x2y2, determine the following: a) Find the fx : b) Find the fy : 4b) c) Find the fxx : 4c d) Find the fyy : 2 4c e) Find the fxy : 4c) 3 f) Find the fyx : 00000 4c)textbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X Dashboard X C D File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas G) find cards saved o... Other Bookmarks 4 / 7 | 79% + 5. (22 points) Sketch the graph of this function using the following guidelines: f (x) = x3 - 3x a) Intercept(s), if any: x - intercept(s) = y - intercept = b) Increasing and decreasing intervals: Increasing interval = Decreasing interval = c) Local Maximum and Minimum Point(s): Local Maximum Point = Local Minimum Point = d) Concave up and concave down intervals: Concave up interval = 2 Concave down interval = e) Inflection Point(s), if any: Inflection Point = Inflection Point = f) Graph: 3 HNW -6 - 5 - 4 - 3 -2 - 10 1 2 3 4 5 6 x 00 000textbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X *Dashboard X C D File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas G) find cards saved o... Other Bookmarks 5 / 7 | 79% + 6. (6 points each) Determine these indefinite integrals: 2x-1 Jx2-x-3" 2 010 0 0 0 6a) b) S V6x - 5 dx 00 000 4 5b)textbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X Dashboard X C D O File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas find cards saved o... Other Bookmarks = 6 / 7 - 79% 2 7. (7 points) Solve the initial value separable differential equation: dx ay = 2x for y (0, -4) 3 7 ) 1010 8. (7 points) Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2 - 7xy = 8 (1, -1) 8 ) .Otextbroker.com X Final Exam Canvas LMS X MATH140-12141 (ONL) X BusCalc.pdf X *Dashboard X C D File | /Users/davidorozco/Downloads/MathG140FinalExam-Summer2023%20(1).pdf Update : Suggested Sites M Gmail YouTube Disney+ canvas find cards saved o... Other Bookmarks = 717 - 79% + 3 (7 points) Draw the graphs of f(x) and g(x) and shade the area between them in the given interval. Then, find the area between the graphs of f(x) and g(x) in the given interval. f(x) = 3 and g(x) = x for -2 5 x$5 SHAWNHOHNWAVO -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 x 5