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THANK YOUU Assuming that the following function is defined properly: def calcutale_it(a, b, c): if a % C == 0 : print(a ** (a //

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Assuming that the following function is defined properly: def calcutale_it(a, b, c): if a % C == 0 : print(a ** (a // b)) What will be the result of the following function call if a is set to 4, b is set to 3, and is set to 2? calcutale_it(a,b,c) PS: In case you don't see the picture of the function, here is the link: https://pasteboard.co/IBJIOHO.png Your answer: 4 6.3496042 error nothing Assuming that the function below is defined properly: def func(number1=8, number2=9, number3=10): if number1 == 8: print("the first") elif number2 number1/2: print("the second") else: print("the third") https://pasteboard.co/JBSZ1J9.png What will be the output of the following function call: func(8,4, 16) Your answer: the first the second the third error

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