The 20kg crate is pushed by 100 N force through a distance d, 1.2 m. The net force arises from the horizontally constant direction applied force and the horizontally friction force, f. Assume that the crate on the flat belt conveyer system is moving at 2 m/s. The net work on the system is given by  W _net  = F _net d.

 

(a) Derive the kinetic energy from the net work equation and determine its value.

(b) Calculate the net work done on the crate by finding the work done by each force that contributes to the net force.

(c) By using work and energy concept, determine the speed at the end of the push.

(d) Determine the type of motion of the crate.

2 m/s f=4N 100 N -d 1.2 m