The 5-kg slender bar is released from rest in the horizontal position shown. At the instant when it has rotated 45, its angular velocity is 4.16 rad/s. At that instant, you need to determine the magnitude of the force exerted on the bar by the pin support. In that process, find one correct answer from the following: 1.2 m mg 45 The angular acceleration of the rod when it is rotated 45 is a = 12.3 rad/s. Acceleration of the centroidal point G is ag = 11.0 e, +3.66 en at that instant. The normal component of the reactive force at the pin is 86.6 N at that instant. Tangential component of the reactive force at the pin is -86.7 N at that instant. The moment of inertia of the rod about the point O is equal to 0.6 kg-m.