The acceleration of a particle is given by

$a_x(t)=-2\mathrm{.}10\frac{m}{s^2}+(3\mathrm{.}07\frac{m}{s^3})t.$

Part A

Find the initial velocity $v_{0x}$ such that the particle will have the same $x-$coordinate at time $t=4\mathrm{.}05s$ as it had at $t=0.$

Express your answer in meters per second.

$v_{0x}=\frac{m}{s}$

Part B

What will be the velocity at time $t=4\mathrm{.}05s?$

Express your answer in meters per second.