Question
The accompanying table shows results from regressions performed on data from a random sample of 21 cars. The response? (y) variable is CITY? (fuel consumption
The accompanying table shows results from regressions performed on data from a random sample of 21 cars. The response? (y) variable is CITY? (fuel consumption in? mi/gal). The predictor? (x) variables are WT? (weight in? pounds), DISP? (engine displacement in? liters), and HWY? (highway fuel consumption in? mi/gal). The equation CITY=?3.17+0.824HWY was previously determined to be the best for predicting city fuel consumption. A car weighs 2710 ?lb, it has an engine displacement of 2.4 ?L, and its highway fuel consumption is 41 mi/gal. What is the best predicted value of the city fuel? consumption? Is that predicted value likely to be a good? estimate? Is that predicted value likely to be very? accurate?
O Exam 4 - Opera X [VPN mylab.pearson.com/Student/PlayerTest.aspx a . . . X Statistics (MATH 1342-4W02) Take a note. 9:44 PM Test: Exam 4 Question 6 of 20 This test: 20 point(s) possible This question: 1 point(s) possible Submit test The accompanying table shows results from regressions performed on data from a random sample of 21 cars. The response (y) variable is CITY (fuel consumption in mi/gal). The predictor (x) variables are WT (weight in pounds), DISP (engine displacement in liters), and HWY (highway fuel consumption in mi/gal). The equation CITY = - 3.17 + 0.824HWY was previously determined to be the best for predicting city fuel consumption. A car weighs 2710 lb, it has an engine displacement of 2.4 L, and its highway fuel consumption is 41 mi/gal. What is the best predicted value of the city fuel consumption? Is that predicted value likely to be a good estimate? Is that predicted value likely to be very accurate? Click the icon to view the table of regression equations. - X Regression Table The best predicted value of the city fuel consumption is Predictor (x) Variables P-Value R2 Adjusted R2 Regression Equation (Type an integer or a decimal. Do not round.) WT/DISP/HWY 0.000 0.944 0.934 CITY = 6.81 - 0.00133WT - 0.257DISP + 0.653HWY WT/DISP 0.000 |0.748 0.720 CITY = 37.6 - 0.00163WT - 1.26DISP The predicted value is likely to be a good estimate and WT/HWY 0.000 0.942 0.936 CITY = 6.73-0.00163WT + 0.672HWY DISP/HWY 0.000 0.935 0.928 CITY = 1.87 - 0.622DISP + 0.708HWY WT 0.000 0.711 0.696 CITY = 42.1 - 0.00609WT DIS 0.000 0.658 0 640 CITY = 28.6 - 3.04DISP HWY 0.000 0.923 0.919 CITY = - 3.17 +0.824HWY Print Done Time Remaining: 02:20:48 Next 831 9:44 PM [) O 1 Clear 5/7/2022Step by Step Solution
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