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The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2906 and standard deviation 530. One randomly selected customer

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2906 and standard deviation 530. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible.

Find the probability that the customer consumes less than 2800 calories.

P(X<2800)=P(Z<53028002906)

=P(Z<0.2)

=F(0.2)

= 0.4207

  • Can someone explain the breakdown of the last part of the equation - What is "z", what is "x", and how does "F=(-0.2)" become the answer of "0.4207"?

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