The answer I got on this (Question #2 below) is wrong.

DIS. 35. (II) A softball player swings a bat, accelerating it from rest to 2.7 rev/s in a time of 0.20 s. Approximate the bat as a 2.2-kg uniform rod of length 0.95m, and compute the torque the player applies to one end of it.Location Moment of Object of axis inertia Axis (a) Thin hoop, Through radius R center R MR2 |Axis Thin hoop, Through radius R central R width W diameter W MR2 + 1MW2 Axis (c) Solid cylinder, Through radius R R center MR2 Axis Hollow cylinder, Through IM(R, + R;) inner radius R 1 center R2 outer radius R2 Axis (e) Uniform sphere, Through radius R center R . MR2 Axis (f) Long uniform rod, Through 12 ML2 length L center Axis (g) Long uniform rod, Through L ML2 length L end Axis Rectangular Through IM( L2 + W2 ) thin plate, center length L, width W2 .) A softball player swings a bat accelerating it from rest to 2.7 rev/s in a time of .2s. Approximate the bat as a 2.2kg uniform rod of length .95m and compute the torque the player applies to one end of it. (5.6) = 2.7 = 13.5 m/s 2 uniform Rod : = Nizz Q. 2 3 ( 2 . 2 ) ( Q . 95 ) = 0. 6966 T= I(d ) 1 8. 6946 ( 13 . 5 ) = 9. 405 x 12 19.4 (8. 90 25 ) ( 2. 2 ) -37. (II) A small 650-g ball on the end of a thin, light rod is rotated in a horizontal circle of radius 1.2 m. Calculate (a) the moment of inertia of the ball about the center of the circle, and (b) the torque needed to keep the ball rotating at constant angular velocity if air resistance exerts a force of 0.020 N on the ball. Ignore the rod's moment of inertia and air resistance.