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the answers are 20. a) -0.174 eV b) -0.608 eV hope that helps. ill make sure to upvote:) thank you 20. The latent heat of
the answers are 20. a) -0.174 eV b) -0.608 eV hope that helps. ill make sure to upvote:) thank you
20. The latent heat of vaporization for a certain acid at room temperature is 19260 J/mole. The molecules have six degrees of freedom in both phases. The work done on it due to its change in volume during condensation is PAV TnRT. (a) Assuming that self-interactions (and hence uo) are negligible in the vapor state, use the above information to calculate uo for this acid (in eV) in the liquid state at room temperature. (b) When 10-2 mole of this acid in the liquid form is added to one liter of b water, both at room temperature, the temperature of the water rises by 0.1 C. What is the depth of the potential well for this acid in waterStep by Step Solution
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