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The answers are: a ) = 3 0 0 0 ppm b ) = Rm = 0 . 0 8 ohm * m c )

The answers are:
a)=3000 ppm
b)=Rm=0.08 ohm*m
c)=Rmf=1.33 ohm*m at 90 F.
=Rmf=0.59 ohm*m at 180 F.
e)=Rmc=0.66 ohm*m at 180 F.
c. Estimate the resistivities of the mud filtrate at 90 and 180F.
d. Can you justify the statistical approximation for predominantly NaCl muds: Rmf=0.75Rm?
e. Estimate the resistivity of the mudcake at 180F.
f. Can you justify the statistical approximation for predominately NaCl muds: Rmc=1.5Rm?
Determine the values of Rm,Rmf, and Rmc at 10,000ft if mud weight =16lbmgal, mud resistivity =0.42*m at 75F, and geothermal gradient =1.1F100ft.
4.5 At the time of logging, the resistivity of a 10lbmgal drilling mud is measured with an instrument on the surface. A value of 1.52-meter is obtained at a temperature of 90F.
a. What is the apparent salinity of the mud?
b. What is the estimated mud resistivity at a depth of 8,600ft in the hole where the formation temperature is 180F?
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