The answers are on the third picture

. Answers Section 10.3 1. Vertex: (0,0). Axis of symmetry: y = 0. Directrix; x = -4. Focus: (4,0) 2. Vertex: (0,0). Axis of symmetry: x = 0. Directrix: y = -1/8. Focus: (0,1/8) 3. Vertex: (0,0). Axis of symmetry: y = 0. Directrix: x = 1/16. Focus: (-1/16,0) 4. Vertex: (2,-1). Axis of symmetry: x = 2. Directrix: y =-3. Focus: (2,1) 5. Vertex: (-1,4). Axis of symmetry: x= -1. Directrix: y =3. Focus: (-1,5) 6. Vertex: (5, 1). Axis of symmetry: y = 1. Directrix: x =4 2/3. Focus: (5 1/3, 1) 7. Vertex: (2, - 4). Axis of symmetry: x = 2. Directrix: y = -3.5 Focus: (2, - 4.5) 8. Vertex: (-2, 2). Axis of symmetry: y = 2. Directrix: x = - 1 2/3 Focus: (-2 1/3, 2) 9. (y- 1)2 = -(xx-3) 10. (y-3)2 = 12(x-2) 11. x2 = 4() -3) 12. (y - 2)2 = 4V2 (x - 2) 13. 2.25 feet above the vertex. 14. 2.25 ftIn problems 17 - 20, find the standard form of the equation for a parabola satisfying the given conditions. 10. Vertex at (2, 3), opening to the right, focal length 3 11. Vertex at (0, 3), focus at (0,4) 12. Vertex at (2, 2); directrix is x - 2 - V2, focus is (2 + V2, 2) O 9 W PDownload A Al Page 3 of 13. A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its axis of symmetry. The receiver is to be located at the focus. If the dish is 12 feet across at its opening and 4 feet deep at its center, where should the receiver be placed? 14. A searchlight is shaped like a paraboloid of revolution. A light source is located 1 foot from the base along the axis of symmetry. If the opening of the searchlight is 6 feet across, find the depth. O