The atmospheric carbon dioxide levels in parts per million (ppm) in a town can be modeled using the function dened by C(t) = 0.00m2 + 0.625 + 300 + 7.8 sin(21rt) where t is in years and t = 0 corresponds to 1960. Find C '(46) and interpret the result. Round to 2 decimal places as needed. Answer: C'(46) : with unit = . The result indicates that at the beginning of 2006 the carbon dioxide level was at the rate given by C '(46)