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The average fruit fly will lay 390 eggs into rotting fruit. A biologist wants to see if the average will be greater for ies that
The average fruit fly will lay 390 eggs into rotting fruit. A biologist wants to see if the average will be greater for ies that have a certain gene modified. The data below shows the number of eggs that were laid into rotting fruit by several fruit flies that had this gene modified. Assume that the distribution of the population is normal. 376, 397, 414, 3721, 393, 331,421,415, 404, 386, 419, 402, 377, 390, 412 What can be concluded at the the a = 0.10 level of significance Level of significance? a. For this study, we should use Select an answer V b. The null and alternative hypotheses would be: H0: 7 V Seleciananswer V H1: ? V Seleciananswer V c. The test statistic ? V (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is '? V or f. Based on this, we should Select an answer V the null hypothesis. g. Thus, the final conclusion is that The data suggest the populaton mean is significantly more than 390 at a = 0.10, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will Lay in rotting fruit is more than 390. The data suggest that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is not significantly more than 390 at a = 0.10, so there is insufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is more than 390. The data suggest the population mean is not significantly more than 390 at a = 0.10, so there is sufficient evidence to conclude that the population mean number of eggs that fruit flies with this gene modified will lay in rotting fruit is equal to 390. . Question 9 The mean number of eggs per person eaten in the United States is 231. Do college students eat a different number of eggs than the average American? The 67 college students surveyed averaged 214 eggs per person and their standard deviation was 81.1. What can be concluded at the Cr = 0.01 level of significance? a. For this study, we should use Select an answer V b. The null and alternative hypotheses would be: Ho: ? V Seleclananswer V H1: '1 V Seleclananswer V c. The test statistic '2 V = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is 7 V a f. Based on this, we should Select an answer V the null hypothesis. g. Thus, the final conclusion is that The data suggest that the populaton mean is significantly different from 231 at a = 0.01, so there is statistically significant evidence to conclude that the population mean number of eggs consumed by college students per year is different from 231. The data suggest that the sample mean is not significantly different from 231 at a = 0.01, so there is statistically insignificant evidence to conclude that the sample mean number of eggs consumed by college students per year is different from 214. The data suggest that the population mean is not significantly different from 231 at a = 0.01, so there is statistically insignificant evidence to conclude that the population mean number of eggs consumed by college students per year is different from 231. h. interpret the p-value in the context of the study. If the population mean number of eggs consumed by college students per year is 231 and if another 67 college students are surveyed then there would be a 93890648896 chance that the sample mean for these 67 students surveyed would either be less than 214 or greater than 248. If the population mean number of eggs consumed by college students per year is 231 and if another 67 college students are surveyed then there would be a 9.08906488% chance that the population mean would either be less than 214 or greater than 248. There is a 9.08906483% chance that the population mean number of eggs consumed by college students per year is not equal to 231. There is a 9.08906488% chance of a Type I error. i. lnterpret the level of significance in the context of the study. If the population mean number of eggs consumed by college students per year is 231 and if another 67 college students are surveyed then there would be a 1% chance that we would end up falsely concluding that the population mean number of eggs consumed by college students per year is different from 231. If the population population mean number of eggs consumed by college students per year is different from 231 and if another 67 college students are surveyed then there would be a 1% chance that we would end up falsely concluding that the population mean number of eggs consumed by college students per year is equal to 231. i:::: 321:6 2:122:233: 52:122.)" mean number of eggs consumed by college The average salary in this city is $46,400. Is the average less for single people? 51 randomly selected [3 y ' single people who were surveyed had an average salary of $40,315 and a standard deviation of 513,930. There is a 1% chance that you will find the chicken that lays the golden eggs. What can be COHClUdEd at the 01 = 0.01 level Of significance? a. For this study, we should use Select an answer V b. The null and alternative hypotheses would be: He: '2 V Selectananswer V H1: ? V Seleclananswer V . Question 10 c. The test statistic ? V = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is '2 V a f. Based on this, we should Selecian answer V the null hypothesis. g. Thus, the final conclusion is that The data suggest that the population mean is not significantly less than 46,400 at a = 0.01, so there is statistically insignificant evidence to conclude that the population mean salary for singles is less than 46,400. The data suggest that the populaton mean is significantly less than 46,400 at a = 0.01, so there is statistically significant evidence to conclude that the population mean salary for singles is less than 46,400. The data suggest that the sample mean is not significantly less than 46,400 at or = 0.01, so there is statistically insignificant evidence to conciude that the sample mean saiary for singles is less than 40,315. h. interpret the p-value in the context of the study. If the population mean salary for singles is $46,400 and if another 51 singles are surveyed then there would be a 01501720656 chance that the sample mean for these 51 singles surveyed would be less than $40,315. II' the population mean salary for singles is $46,400 and if another 51 singles are surveyed then there would be a 01501720696 chance that the population mean salary for singles would be less than $46,400. There is a 0.1501 7206311 chance that the population mean salary for singles is less than $46,400. There is a 0.15017206% chance of a Type I error. i. Interpret the level of significance in the context of the study. There is a 1% chance that the population mean salary for singles is less than $46,400. If the population mean salary for singles is $46,400 and if another 51 singles are surveyed then there would be a 1% chance that we would end up falseiy concluding that the population mean salary for singles is less than $46,400. If the population population mean salary for singles is less than $46,400 and if another 51 singles are surveyed then there would be a 1% chance that we would end up falsely concluding that the population mean salary for singles is equai to $46,400. There is a 1% chance that you won the lottery, so you may not have to even have to worry about passing this class. . Question 11 The average house has 15 paintings on its wails. Is the mean different for houses owned by teachers? The data show the results of a survey of 15 teachers who were asked how many paintings they have in their houses. Assume that the distribution of the population is normal. 18,15,16,18,17,18,15,14,14,15,18,15,15,14,17 What can be conciuded at the or = 0.10 level of significance? a. For this study, we shouid use Select an answer V b. The null and alternative hypotheses would be: Hg! '2 V Selectananswer V H1: '2 V Selectananswer V c. The test statistic 7 V = (please show your answer to 3 decimal places.) d. The p-value = (Piease show your answer to 4 decimal places.) e. The p-value is '2 V or f. Based on this, we should Select an answer V the null hypothesis. g. Thus, the final conclusion is that The data suggest the populaton mean is significantly different from 15 at a = 0.10, so there is sufficient evidence to conclude that the population mean number of paintings that are in teachers' houses is different from 15. The data suggest that the population mean number of paintings that are in teachers houses is not significantly different from 15 at a = 0.10, so there is insufficient evidence to conclude that the population mean number of paintings that are in teachers' houses is different from 15. The data suggest the population mean is not significantly different from 15 at or = 0.10, so there is sufficient evidence to conclude that the population mean number of paintings that are in teachers' houses is equal to 15. h. lnterpret the pvaiue in the context of the study. There is a 3.82% chance of a Type I error. If the population mean number of paintings that are in teachers' houses is 15 and if you survey another 15 teachers then there would be a 3.82% chance that the population mean would either be less than 14 or greater than 16. If the population mean number of paintings that are in teachers' houses is 15 and if you survey another 15 teachers, then there would be a 3.82% chance that the sampie mean for these 15 teachers would either be less than 14 or greater than 16. There is a 3.82% chance that the popuiation mean number of paintings that are in teachers' houses is not equal to 15. i. lnterpret the level of significance in the context of the study. If the population mean number of paintings that are in teachers' houses is 15 and if you survey another 15 teachers, then there would be a 10% chance that we would end up falsely concuding that the population mean number of paintings that are in teachers' houses is different from 15. If the population mean number of paintings that are in teachers' houses is different from 15 and if you survey another 15 teachers, then there would be a 10% chance that we would end up falsely concuding that the population mean number of paintings that are in teachers houses is equal to 15 According to the Carnegie unit system, the recommended number of hours students should study per ' unit is 2. Are statistics students' study hours more than the recommended number of hours per unit? There is a 10% chance that the population mean number af paintings that are in teachers' The data show the results of a survey of 13 statistics students who were asked how many hours per unit houses is different from 15. they studied. Assume a normal distribution for the population. There is a 10% chance that teachers are so poor that they are all homeless. 2.3, 0,5, 1.1, 1.4, 3.5, 2,2, 0.7, 1,7, 3, 2.9, 3.1, 0.9, 1.8 What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer V b. The null and alternative hypotheses would be: Hg: 'P v Seleclan answer V H1: 9 v Select an answer v . Question 12 c. The test statistic ? V = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places} e. The p-valueis ? V a f. Based on this, we should Selectan answer V the null hypothesis. g. Thus, the final conclusion is that The data suggest the populaton mean is significantly more than 2 at a = 0.10, so there is sufficient evidence to conclude that the population mean study time per unit for statistics students is more than 2. The data suggest the population mean is not significantly more than 2 at a = 0.10, so there is sufficient evidence to conclude that the population mean study time per unit for statistics students is equal to Z. The data suggest that the population mean study time per unit for statistics students is not significantly more than 2 at a = 0.10, so there is insufficient evidence to conclude that the population mean study time per unit for statistics students is more than 2. h. interpret the pvalue in the context of the study. There is a 30% chance that the population mean study time per unit for statistics students is greater than 2. There is a 50% chance of a Type I error. If the population mean study time per unit for statistics students is 2 and if you survey another 13 statistics students then there would be a 50% chance that the population mean study time per unit for statistics students would be greater than 2. If the population mean study time per unit for statistics students is 2 and if you survey another 13 statistics students then there would be a 50% chance that the sample mean for these 13 statistics students would be greater than 2. ii interpret the ievel of significance in the context of the study. If the population mean study time per unit for statistics students is 2 and if you survey another 13 statistics students, then there would be a 10% chance that we would end up falsely concuding that the population mean study time per unit for statistics students is more than 2. If the population mean study time per unit for statistics students is more than 7. and if you survey another 13 statistics students, then there would be a 10% chance that we would end up falsely concuding that the population mean study time per unit for statistics students is equal to 2' There is a 10% chance that students just don't study at all so there is no point to this survey There is a 10% chance that the pcpulation mean study time per unit fur statistics students is more than 2
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