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The bank manager wants to show that the new system reduces typical customer waiting times to less than 6 minutes. One way to do this

The bank manager wants to show that the new system reduces typical customer waiting times to less than 6 minutes. One way to do this is to demonstrate that the mean of the population of all customer waiting times is less than 6. Letting this mean be, in this exercise we wish to investigate whether the sample of 96 waiting times provides evidence to support the claim thatis less than 6.

For the sake of argument, we will begin by assuming thatequals 6, and we will then attempt to use the sample to contradict this assumption in favor of the conclusion thatis less than 6. Recall that the mean of the sample of 96 waiting times is= 5.46 and assume that , the standard deviation of the population of all customer waiting times, is known to be 2.21.

(b)Find the mean and standard deviation of the population of all possible sample means when we assume thatequals 6.(Round your answer to 4 decimal places.)

x= 6,x=

(c)The sample mean that we have actually observed is= 5.46. Assuming thatequals 6, find the probability of observing a sample mean that is less than or equal to= 5.46.(Round your answer to 4 decimal places.)

P(<5.46)

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