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The boiling point of a compound at P = 0 . 1 MPa is 1 5 0 K . The Linde liquefaction process will be

The boiling point of a compound at P =0.1 MPa is
150 K. The Linde liquefaction process will be used to
produce saturated liquid at P =0.1 MPa, which has
a specific enthalpy of 20 kJ/kg. The Table P5-14 in
the right-hand column contains some physical properties of the compound. The steady-state process
works as follows.
Step 1.50 kg/minute enters the process at T =250
K and P =0.1 MPa.
Step 2. The feed enters a series of compressors and
heat exchangers, and it leaves the last heat
exchanger at T =200 K and P =10 MPa.
The TOTAL work added by the compressors is 300 kilojoules per kilogram of feed.
Step 3. The stream leaving step 2 is cooled to T =
175 K in a heat exchanger.
Step 4. The stream leaving step 3 enters a flash
chamber where it expands to 0.1 MPA and
some of it condenses.
Step 5. The vapor from the flash chamber is used
as the coolant for the heat exchanger in
step 3.
Step 6. The vapor stream (at P =0.1 MPA) from
step 5 is NOT recycled; it exits the process
as a by-product.
A. Find the flow rate of liquid product leaving the
flash chamber.
B. Find the specific enthalpy (kJ/kg) of the vapor
by-product described in step 6.
C. Find the total heat removed by the heat exchangers during step 2, in kJ/min.
D. What is the heat capacity of the compound, in
kJ/kg ? K, at ideal gas conditions?

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