The British Department of Transportation studied to see if people avoid driving on Friday the 13th. They did a traffic count (in cars) on a Friday 6th and then again on a Friday the 13th at the same location. The data for a random sample of locations on the two different dates are in the table below. Do the data show that on average fewer people drive on Friday the 13th? a) Test at the 2% level. b) Compute a 96% confidence interval for the difference. Traffic counts at locations on Friday the 6th Traffic counts at locations on Friday the 13th (in cars) (in cars) 121139 118723 139246 138548 133732 131843 124631 120249 124609 122770 117584 117263 123552 121641 128293 123532O: Obtain the P-value Report the final answer to 4 decimal places. It is possible when rounded that a p-value is 0.0000 P-value M: Make a decision Since the p-value Ev we fail to reject H. v . S: State a conclusion . There is significant evidence to conclude The traffic count of a randomly selected location on a Friday the 6th Select an answer v The traffic count of a randomly selected location on a Friday the 13th v Part b.)_CONFIDENCE INTERVAL N: Name the procedure 1-Proportion Z-Interval v I: Interval estimate (round endpoints to 1 decimal place(s)) % confidence interval for p, - P. is ( cars, cars ) C: Conclusion in context . If your interval above contains 0, then we don't care about the interpretation since there was no significant difference in these means. In this case, just enter "0" for each of the endpoints below (the program won't let you leave them blank). On your homework guide you should write "We don't interpret the interval when there is no evidence of a difference" . We are * confident that The mean traffic count of all locations on a Friday the 6th is between cars and cars more than The mean traffic count of all locations on a Friday the 13th2. Is the value of o unknown for each group? |Now 3. Are there any outliers in the differences? Yes, the normal probability plot shows outliers 4. n = which is ? Is it reasonable to assume the population is normally distributed? Select an answer v N: Name the test The conditions are met to use a |Select an answer v . T: Test Statistic The symbol and value of the random variable on this problem are as follows: This computation assumes you calculated L3 as L3= L1 - L2. Round your answers to 1 decimal places. Select an answer ~|= cars Set up the formula for the test statistic with numbers to 1 decimal places: d t: sd Final answer from technology to 2 decimal places: t =