The circuit in the gure below contains a 90.0 V battery and four capacitors. In the top parallel branch, there are two capacitors, one with a capacitance of C1 = 4.00 pF and another with a capacitance of 6.00 pF. In the bottom parallel branch, there are two more capacitors, one with a capacitance of 2.00 [JF and another with a capacitance of C2 = 9.00 pF. (x (molar | | | | | | | | | 2.00 M (g + l 901) v Q (a) What is the equivalent capacitance (in pF) of the entire circuit? pF (b) What is the charge (in uC) on each capacitor? on C1 M: on C2 pC on the 6.00 pF capacitor uC on the 2.00 uF capacitor uC (c) What is the potential difference (in V) across each capacitor? across C1 V across C2 V across the 6.00 pF capacitor V across the 2.00 uF capacitor V 2. [-/2 Points] SERCP11 16.7.0P.051. ASK YOUR TEACHER A lab technician builds a parallel-plate capacitor with adjustable spacing between the plates. when the plates are at their initial separation, the capacitance is 9.00 pF. (a) At this capacitance, the capacitor is connected to a 18.00 V battery. After fully charging, how much energy (in pJ) is stored in the capacitor? pJ (b) The battery is then disconnected. Without discharging the capacitor, the lab technician then doubles the separation between the plates. At this point, how much energy (in pJ) is stored in the capacitor? pJ (c) Without changing this new separation between the plates, the capacitor is discharged, and then reconnected to the 18.00 V battery. Now, after fully charging, how much energy (in pJ) is stored in the capacitor? pJ 3. [-/2 Points] DETAILS MY NOTES ASK YOUR TEACHER For the system of four capacitors shown in the figure below, find the following. (Use C, = 5.00 UF, C2 = 4.00 HF, C3 = 6.00 UF, and C4 = 1.00 UF for the figure.) CIUF C2HF C UF 90.0 V (a) the total energy stored in the system mJ (b) the energy stored by each capacitor C1 mJ C2 mJ C3 mJ CA mJ4. [-/2 Points] DETAILS SERCP11 16.8.P.056. MY NOTES ASK YOUR TEACHER A parallel plate capacitor has plates of area A = 6.50 x 10-2 m separated by distance d = 2.07 x 10-4 m. (The permittivity of free space is . = 8.85 x 10-12 C2/(N . m2).) HINT (a) Calculate the capacitance (in F) if the space between the plates is filled with air. What is the capacitance (in F) if the space is filled half with air and half with a dielectric of constant k = 2.30 as in figure (a), and figure (b)? (Hint: One of the capacitors is a parallel combination and the other is a series combination.) K - 2 - K a b (b) figure (a) F (c) figure (b) F Submit Answer 5. [-/2 Points] DETAILS SERCP11 16.A.P.063.MI. MY NOTES ASK YOUR TEACHER A parallel-plate capacitor is constructed using a dielectric material whose dielectric constant is 3.80 and whose dielectric strength is 1.20 x 10 V/m. The desired capacitance is 0.100 JF, and the capacitor must withstand a maximum potential difference of 4.00 kV. Find the minimum area of the capacitor plates. m