The class is about Electricity and Magnetism. The website wants exactly the perfect answer and in the same metric system units that are stated on the calculators that are on the picture for the question, if not, it'll mark it wrong.

Dielectric-Filled Capacitor v Id = 3.0 mm K= 3.6 3.0 mm A parallel plate capacitor with plate area A = 242 m and plate separation 3.0 mm is connected to a 49-V battery. a. Determine the charge O on the capacitor, the magnitude IEl of the electric field, the capacitance C, and the energy U stored in the capacitor. 0 = abc sin(x) 1x10' Submit Reset Reset All .You may find it easier to find the quantities in a different order than the one listed. O . LEI= V/m abc sin (x) x10' Submit Reset Reset All C= abc apy sin( x x10 Submit Reset Reset Allb. \"rim the capacitor still connected to the battery, a slab of plastic With dielectric strength K = 3.6 is placed between the plates of the capacitor, so that the gap is completely lled with dielectric. What are the new values of charge, magnitude of the electric eld. capacitance, and the energy stored in the capacitor? C = F abc sin(x 1x10" Submit Reset Reset All U = abo sin(x) Ox10 Submit Reset Reset All