The class is about Electricity and Magnetism. The website wants exactly the perfect answer and in the same metric system units that are stated on the calculators that are on the picture for the question, if not, it'll mark it wrong.

Inductive Heater A 35.6-cm-diameter coil consists of 21 turns of circular copper wire 2.08 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 3.51 x 10- T/s. Determine a. the current / in the loop, 5 abo sin(x) 0x10 Submit Reset Reset All First find the resistance of the coil. See Table 25-1 for the resistivity of copper. Remember that the effective area of the coil is 21 times the area of one turn, since each turn is threaded by the changing flux. b. and the rate do/dr at which thermal energy is produced. 5 O. du/dt = abc sin(x Ox10 Submit Reset Reset All .A more familiar way of the asking the same question is to ask for the power dissipated in the coil.TABLE 25-1 Resistivity and Temperature Coefficients (at 20 C) Resistivity, Temperature Material p (2 . m) Coefficient, a (Co) -1 Conductors Silver 1.59 X 10-8 0.0061 Copper 1.68 X 10 8 0.0068 Gold 2.44 X 10 8 0.0034 Aluminum 2.65 x 10-8 0.00429 Tungsten 5.6 X 10 8 0.0045 Iron 9.71 X 10-8 0.00651 Platinum 10.6 X 10 8 0.003927 Mercury 98 X 10 8 0.0009 Nichrome (Ni, Fe, Cr alloy) 100 X 10 8 0.0004 Semiconductors Carbon (graphite) (3-60) x 10 5 -0.0005 Germanium (1-500) X 10 3 -0.05 Silicon 0.1-60 -0.07 Insulators Glass 109 - 1012 Hard rubber 1013-1015 * Values depend strongly on the presence of even slight amounts of impurities