The class is about Electricity and Magnetism. The website wants exactly the perfect answer and in the same metric system units that are stated on the calculators that are on the picture for the question, if not, it'll mark it wrong.

PE A sphere of radius ro = 5.1 cm carries a volume charge density p = 0.071 uC/m. A spherical cavity of radius ro/2 is then scooped out and left empty, as shown above. What is the magnitude and direction of the electric field E at point A? Give a positive answer if the electric field points to the right, negative if to the left. O. 15 2 EA= N/C abc sin ( x 1x10 Submit Reset Reset All .You can think of the given charge configuration, which lacks spherical symmetry, as a combination of two spherically symmetric charge distributions: a sphere of radius ro with positive charge density o and a sphere of radius ro/2 with negative charge density -9. Note that where the two charge distributions overlap, there will be zero net charge density. .Considering each of the two spherically symmetric charge distributions independently, you can use Gauss' law to find the electric field at any point. Then make use of the Superposition Principle to find the net electric field. What is the magnitude and direction of the electric field E at point B? Give a positive answer if the electric field points to the right, negative if to the left. 5 5 EB N/C abc sin(x) 0x10 Submit Reset Reset All