The complexity of the algorithm below is O$(1).$

if $($timeHour $<6)\{$

tollAmount $=1\mathrm{.}55$

$\}$

else if $($timeHour $<10)\{$

tollAmount $=4\mathrm{.}65$

$\}$

else if $($timeHour $<18)\{$

tollAmount $=2\mathrm{.}35$

$\}$

else $\{$

tollAmount $=1\mathrm{.}55$

$\}$