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The conditional pdfs corresponding to two hypotheses are given: exp(-x), x0 f(x|H)=- and f(x H)= [1/2, 0, x <0 0, 2 x 4 else
The conditional pdfs corresponding to two hypotheses are given: exp(-x), x0 f(x|H)=- and f(x H)= [1/2, 0, x <0 0, 2 x 4 else Using one observation X, what is the decision rule that maximizes PD for a PFA = exp(-4)? Be sure to calculate the threshold that yields the desired PFA.
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