The construction of a water pistol is shown in the figure below. The cylinder with cross-sectional area A, is filled with water and when the piston is pushed (by pulling the trigger), water is forced out the tube with cross-sectional area A,. The radius of the cylinder and tube are, respectively, 1.50 cm and 1.50 mm, and the center of the tube is a height h = 3.00 cm above the center of the cylinder. (Assume atmospheric pressure is 1.013 x 105 pa.) C (a) If the pistol is fired horizontally at a height of 1.10 m, determine the time interval (in s) required for water to travel from the nozzle to the ground. Neglect air resistance. 0.473709 (b) If the desired range of the stream is 7.70 m, with what speed v, (in m/s) must the stream leave the nozzle? 16.25 m/s (c) At what speed v, (in m/s) must the plunger be moved to achieve the desired range? 0.13 X The speed of the fluid (v, and v, ) at points 1 and 2 is related to the cross-sectional areas (A, and A, ) by the continuity equation. Knowing the radius of the cylinder and tube, you can determine their cross-sectional area. m/s (d) What is the pressure (in Pa) at the nozzle? 113000 X Since the nozzle is open to the atmosphere, how should the pressure P2 compare to atmospheric pressure Po? Pa (e) Find the pressure (in Pa) needed in the cylinder. (f) Calculate the force (in N) that must be exerted on the trigger to achieve the desired range. (The force that must be exerted is due to pressure over and above atmospheric pressure. Enter the magnitude.)