Question
The consumption of tungsten (in metric tons) in a country is given approximately by p(t)=138t2+1,071t+14,910, where t is time in years and t=0 corresponds to
The consumption of tungsten (in metric tons) in a country is given approximately by
p(t)=138t2+1,071t+14,910,
where t is time in years and
t=0
corresponds to 2010.(A) Use the four-step process to find
p(t).
(B) Find the annual consumption in
2028
and the instantaneous rate of change of consumption in
2028,
and write a brief verbal interpretation of these results.
example-
The consumption of tungsten (in metric tons) in a country is given approximately by
p(t)=136t2+1,072t+14,905,
where t is time in years and
t=0
corresponds to 2010.
(A) Use the four-step process to find
p(t).
(B) Find the annual consumption in
2025
and the instantaneous rate of change of consumption in
2025,
and write a brief verbal interpretation of these results.
(A) For
y=f(x),
the derivative of f at x, denoted
f(x),
is defined by the formula below, provided the limit exists.
f(x)=limh0f(x+h)f(x)h
First find
p(t+h).
Substitute
t+h
for t in the formula for p(t).
p(t+h) | = | 136(t+h)2+1,072(t+h)+14,905 |
Now determine
p(t+h)p(t).
p(t+h)p(t) | = | 136(t+h)2+1,072(t+h)+14,905136t2+1,072t+14,905 |
= | 136t2+2ht+h2+1,072(t+h)+14,905136t2+1,072t+14,905 | |
= | 136t2+272ht+136h2+1,072t+1,072h+14,905136t21,072t14,905 | |
= | 272ht+136h2+1,072h |
Next find
p(t+h)p(t)h.
p(t+h)p(t)h | = | 272ht+136h2+1,072hh | |
= | h(272t+136h+1,072)h | Factor h out of the numerator. | |
= | 272t+136h+1,072 | Simplify. |
Finally, determine
p(t)
by finding the limit of
p(t+h)p(t)h
as h approaches 0. Notice that since
272t+136h+1,072
is a polynomial, the limit is the same as evaluating the expression at
h=0.
p(t) | = | limh0 p(t+h)p(t)h | |
= | limh0 (272t+136h+1,072) | ||
= | 272t+1,072 | Calculate the limit. |
Therefore,
p(t)=272t+1,072.
(B) To find the annual consumption in
2025
and the instantaneous rate of change of consumption in
2025,
first determine the t-value corresponding to year
2025.
t=15
To find the annual consumption in
2025,
evaluate the function
p(t)=136t2+1,072t+14,905
at
t=15.
p(t) | = | 136t2+1,072t+14,905 | |
p(15) | = | 136(15)2+1,072(15)+14,905 | Substitute 15 for t. |
= | 61,585 | Simplify. |
To find the instantaneous rate of change of consumption in
2025,
evaluate the function
p(t)=272t+1,072
at
t=15.
p(t) | = | 272t+1,072 | |
P(15) | = | 272(15)+1,072 | Substitute 15 for t. |
= | 5,152 | Simplify. |
Therefore, the annual consumption in
2025
is
61,585
metric tons and the instantaneous rate of change of consumption in
2025
is
5,152
metric tons.
This means that in
2025,
61,585
metric tons of tungsten are consumed and this quantity is increasing at the rate of
5,152
metric tons per year.
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