The crew of a stationary spacecraft observe an asteroid whose mass is $3\mathrm{.}00\backslash$times $1017$kg$.$ Taking the location of the spacecraft as the origin, the asteroid is observed to be at location $-2\mathrm{.}60\backslash$times $103,-4\mathrm{.}80\backslash$times $103,8\mathrm{.}00\backslash$times $103$m at a time $16\mathrm{.}6$s after lunchtime. At a time $22\mathrm{.}4$s after lunchtime, the asteroid is observed to be at a location $-1\mathrm{.}00\backslash$times $103,-5\mathrm{.}20\backslash$times $103,1\mathrm{.}01\backslash$times $104$m$.$ Assuming that the velocity of the asteroid does not change during this time interval, calculate the vector velocity v$$ of the asteroid.

v$=$