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The current in the figure below is0.62A. (Let the internal resistance of battery 1 be r 1 =1.4 and the internal resistance of battery 2
The current in the figure below is0.62A. (Let the internal resistance of battery 1 be
r1=1.4
and the internal resistance of battery 2 be
r2=1.2.)
(a) Find the voltage dropVab. (b) Find the power dissipated inR. (c) Find the useful electric power supplied by battery 2. (Note:Do not forget the internal resistance of battery 2.) (d) Find the rate at which chemical energy is stored in battery 1. (Note:Do not include power dissipated in the internal resistor of battery 1 in your answer.)
The current in the gure below is 0.62 A. (Let the internai resistance of battery 1 be r1 = 1.4 Q and the internal resistance of battery 2 be r2 = 1.2 .) (a) Find the voltage drop Vab- |:| [b] Find the power dissipated in R. |:| (c) Find the useful electric power supplied by battery 2. (Note: Do not forget the internal resistance of battery 2.) |:| (d) Find the rate at which chemical energy is stored in battery 1. (Note: Do not include power dissipated in the internal resistor of battery 1 in your answer.) |:|Step by Step Solution
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