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The data for a sample of 80 steel parts, given in Q1 of M9-Assignment.xlsx, shows the reported difference, in inches, between the actual length of
- The data for a sample of 80 steel parts, given in Q1 of M9-Assignment.xlsx, shows the reported difference, in inches, between the actual length of the steel part and the specified length of the steel part. For example, a value of minus 0.002 represents a steel part that is 0.002 inch shorter than the specified length.
- (12 points) At the 0.05 level of significance, is there evidence that the mean difference is more than 0.0 inches? State the null and alternative hypotheses.
- (3 points) Do you have to be concerned about the normality assumption?
- (15 points) According to a recent report, 48% of college student internships are unpaid. A recent survey of a group of college interns is shown in Q2 of the M9-Assignment.xlsx.
- Use p-value approach to hypothesis testing and a 0.10 level of significance to determine whether the proportion of college interns that had unpaid internships is different from 0.48. State the null and alternative hypotheses.
0.001 |
0.003 |
0.0015 |
0.003 |
0.003 |
-0.001 |
-0.002 |
0.0005 |
0.002 |
-0.003 |
0.001 |
-0.001 |
0.003 |
0.001 |
-0.003 |
-0.002 |
-0.0025 |
0.0025 |
-0.003 |
-0.001 |
-0.0025 |
0.002 |
-0.0025 |
0.0015 |
-0.001 |
0.001 |
0.003 |
-0.003 |
-0.0025 |
0.001 |
0.0005 |
0.001 |
0.001 |
0.003 |
-0.0015 |
0.001 |
-0.002 |
-0.002 |
0.0015 |
0.0015 |
0.0005 |
-0.0015 |
-0.0015 |
-0.0005 |
0.002 |
-0.003 |
0.001 |
0.001 |
-0.0005 |
-0.001 |
-0.002 |
-0.002 |
0.001 |
0.0015 |
-0.0015 |
0.0005 |
0.001 |
-0.0015 |
0.0025 |
-0.0015 |
0.0005 |
-0.001 |
0.0025 |
0.0015 |
-0.0025 |
0.002 |
-0.003 |
-0.0025 |
0 |
-0.0005 |
-0.0025 |
0.0005 |
0.002 |
-0.001 |
0.0015 |
0.003 |
0.0025 |
0.003 |
0.002 |
0.003 |
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