Question
The data for a sample of 80 steel parts, given in the accompanying table, show the reported difference, in inches, between the actual length of
The data for a sample of 80 steel parts, given in the accompanying table, show the reported difference, in inches, between the actual length of the steel part and the specified length of the steel part. For example, a value of 0.002 represents a steel part that is 0.002 inch shorter than the specified length. Complete parts (a) through (d).
At the 0.20 level of significance, is there evidence that the mean difference is different from 0.0
inches?
A.) Already completed.
B.) Find tSTAT
C.) Find P-value
D.) Construct a 95% CF interval estimate of the population mean:
Use graph:
-0.0015 |
0.0015 |
-0.002 |
0.0015 |
-0.0015 |
0.0005 |
-0.001 |
-0.003 |
-0.0015 |
-0.001 |
0.0005 |
0.002 |
-0.003 |
0.003 |
-0.0025 |
-0.003 |
0.001 |
-0.0015 |
-0.0015 |
0.0015 |
-0.0005 |
-0.0025 |
-0.001 |
0.0025 |
-0.0015 |
0.0005 |
0.0005 |
0.0015 |
0.0015 |
0.0005 |
0.0015 |
0.001 |
-0.002 |
0.0015 |
-0.0025 |
0.0005 |
0.0005 |
0.001 |
0.002 |
-0.001 |
0.003 |
0.001 |
-0.0005 |
-0.002 |
0.0025 |
0.003 |
0.0015 |
0.0015 |
0.001 |
0.0025 |
0.0005 |
-0.0015 |
-0.001 |
-0.002 |
-0.0015 |
-0.001 |
-0.002 |
0.002 |
0.0015 |
0.002 |
-0.0025 |
-0.0025 |
-0.0015 |
-0.001 |
0.001 |
0.0025 |
-0.0005 |
0.003 |
0.0015 |
-0.0005 |
0.001 |
-0.0005 |
0.002 |
0.0025 |
-0.001 |
-0.0015 |
0.0005 |
0.001 |
-0.001 |
-0.0015 |
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