The data show the number of viewers for television stars with certain salaries, Find the regression equation, letting salary be the independent (x) variable, Find the best predicted number of viewers for a television star with a salary of $11 million. Is the result close to the actual number of viewers, 1.8 million? Use a significance level of 0.05. Salary (millions of $) Viewers (millions) 111 7 5 6 13 7 4 10 9.4 6.8 5.7 4.3 1.1 6.2 1.5 6.9 Click the icon to view the critical values of the Pearson correlation coefficient r. Critical Values of the Pearson Correlation Coefficient - X What Is the regression equation? "=]+ (Round to three decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r What is the best predicted number of viewers for a television star with a salary of $11 million? C = 0.05 or = 0.01 NOTE: To test Hop =0 0.950 0.990 against Hip #0, reject Ho The best predicted number of viewers for a television star with a salary of $11 million is |million. 0.878 0.959 if the absolute value of r is (Round to one decimal place as needed.) 0.811 0.91 greater than the critical 0.754 0.875 value in the table Is the result close to the actual number of viewers, 1.8 million? 0.707 0.834 0.666 0.798 O A. The result is exactly the same as the actual number of viewers of 1.8 million. 0.632 0.765 0.602 0.735 O B. The result is very close to the actual number of viewers of 1.8 million. 0.576 0.708 O C. The result is not very close to the actual number of viewers of 1.8 million. 0.553 0.68 0.532 0.66 O D. The result does not make sense given the context of the data. 0.51 0.64 0.497 0.623 0.482 0.606 0.468 0.590 0.456 0.575 0.444 0.561 0.396 0.505 0.361 0.463 0.335 0.430 0.312 0.402 0.294 0.378 0.279 0.361 0.254 0.330 0.236 0.305 0.220 0.286 W E W WW ww WWOWNNNNNN 0.207 0.269 0.196 0.256 a = 0.05 = 0.01 Print Done