The decomposition of nitrous oxide at $565C$

$N_{2}O(g)N_2(g)+\frac{1}{2}{O}_2(g)$

is second order in $N_{2}O$ with a rate constant of $1\mathrm{.}10{10}^{-3}\frac{1}{M*s}.$

If the initial concentration of $N_{2}O$ is $1\mathrm{.}07M,$ the concentration of $N_{2}O$ will be M after $4670$ seconds have passed.