The degree 3 least sqaures approximation to the points {(1,2), (2, 3), (3, 4), (4, 1), (5,2), (6,3)} is drawn in the picture below. To find this approximation, 2 3 1 1 1 1 12 4 8 13 9 27 14 16 64 1 5 25 125 . This equation Ax=b has no solution because b is not in the column space of A. Find the projection 1 2 1 6 36 216 3 of b (call the projection p) to the column space of A so that Ax = p has a solution. Give the sum of the entries of p as the answer, to the nearest thousandth (three points after the decimal). we begin with the matrix equation Answer: b R R